A iron casting containing a number of cavities 6000 N in air and 4000

1.	A iron casting containing a number of cavities 6000 N in air and 4000 N in water. The volume ofcavities in the casting is x ty of water is I g/cm3,ng 1sx102 m3. (density of iron is 7.87g/cm, densi
Answer» Loss in weight when iron casting weighed in water=6000-4000 =2000 N According to Archimedes principle, Loss in wt in water = wt of equal volume of water volume of displaced water= V =weight/ (densityg) volume of displaced water= V =2000/1000g volume of displaced water= V = 2 /g m^3 Actual volume of iron in casting = Vi = weight / (density of irong) Vi=6000/7870g=0.7624 /g volume of cavity = vol. of displaced water - vol. of iron volume of cavity=2/g -0.7624/g=1.2376 /g volume of cavity =0.012628 m^3 =12628 cc the total volume of all the cavities in the casting is 0.012628 m^3 or 12628 cc

A iron casting containing a number of cavities 6000 N in air and 4000 N in water. The volume ofcavities in the casting is x ty of water is I g/cm3,ng 1sx102 m3. (density of iron is 7.87g/cm, densi

Answer»

Loss in weight when iron casting weighed in water=6000-4000 =2000 N

According to Archimedes principle,

Loss in wt in water = wt of equal volume of water

volume of displaced water= V =weight/ (density*g)

volume of displaced water= V =2000/1000*g

volume of displaced water= V = 2 /g m^3

Actual volume of iron in casting = Vi = weight / (density of iron*g)

Vi=6000/7870*g=0.7624 /g

volume of cavity = vol. of displaced water - vol. of iron

volume of cavity=2/g -0.7624/g=1.2376 /g

volume of cavity =0.012628 m^3 =12628 cc

the total volume of all the cavities in the casting is 0.012628 m^3 or 12628 cc

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