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A jet airplance travelling at the speed of ` 500 km ^(-1)` ejects its products of combustion at the speed of ` 1500 km h^(-1)` relative to the jet plane. What is the speed of the burnt gases with respect to observer on the ground ?A. 1500 km/hB. 2000km/hC. 1000km/hD. 500km/h |
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Answer» Correct Answer - C `V_("gas,plane")=V_("gas")+V_("plane")` `V_("gas")=V_("gas,plane")-V_("plane")` `=1500-500=1000lkm//h` |
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