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A juggler maintains four balls in vertically upwards motion. He attempts next ball after `(1)/(4)` seconds. For the show to go one, what should be the height for which he thrwos the ball ? `(g = 10 m//s^(2))`A. 1.25 mB. 5 mC. 2.5mD. 1.0 m |
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Answer» Correct Answer - A `H = (1)/(2) xx g xx ((1)/(2))^(2)` `H = 1.25 m` Time for one ball to reach at max. height is `(1)/(4) + (1)/(4) = (1)/(2)` sec |
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