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A junction diode has a resistance of 25 `Omega` when forward biased and 2500 `Omega` when reverse biased. What is the current in the diode, for the arrangement shown ? A. `1/25A`B. `1/7A`C. `1/35A`D. `1/480A` |
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Answer» Correct Answer - B In this case, V = 5 V. The diode is forward biased. Net resistance= `10Omega +25 Omega = 35 Omega` `therefore I=V/R =5/35 =1/7A` (No current in reverse bias) |
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