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The depletion layer in diode is `1 mum` wide and the knee potential is `0.6 V`, then the electric field in the depletion layer will beA. `5xx10^(6)Vm^(-1)`B. `5xx10^(-7)Vm^(-1)`C. `5xx10^(5)Vm^(-1)`D. `5xx10^(-1)Vm^(-1)` |
Answer» Correct Answer - C In forward biasing condition, the linner electric field is given by `E=(DeltaV)/(Deltar)` `or |E|=(DeltaV)/(Deltar)=(5xx10^(-1))/(10^(-6))` `=5xx10^(5) Vm^(-1)` |
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