(i) calculate the value of output voltage `V_(0)` and current `I` if silicon diode and germanium diode conduct at `0.7V` and `0.3 V` respectively. Fig. (ii) If now germanium diode is cinnected to `12 V` in reverse polarity, find new values of `V_(0)` and `I`.

(i) calculate the value of output voltage `V_(0)` and current `I` if s

1.	(i) calculate the value of output voltage `V_(0)` and current `I` if silicon diode and germanium diode conduct at `0.7V` and `0.3 V` respectively. Fig. (ii) If now germanium diode is cinnected to `12 V` in reverse polarity, find new values of `V_(0)` and `I`.
Answer» As Ge diode conducts at `0.3V`, both Ge and Si are in parallel, so `p.d.` across each is `0.3V`. At `0.3V`, Si diode offers infinite resistance and it does not conduct. `p.d.` across `R=5kOmega` is `12-0.3=11.7V` `V_(0)11.7V` `i=(V_(0))/(R )=(11.7)/(5xx10^(3))=2.34mA` When the connection of Ge diode are reversed, it will be in reverse biased and for conduction, the `p.d.` across the silicon diode will be `0.7V` `p.d.` across `R=5kOmega` is `12-0.7=11.3V` `V_(0)=11.3V` `i=(V_(0))/(R )=(11.3)/(5xx10^(3))=2.26mA`

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(i) calculate the value of output voltage `V_(0)` and current `I` if silicon diode and germanium diode conduct at `0.7V` and `0.3 V` respectively. Fig. (ii) If now germanium diode is cinnected to `12 V` in reverse polarity, find new values of `V_(0)` and `I`.

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