InterviewSolution
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InterviewSolution
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A lift a mass `1200 kg` is raised from rest by a cable with a tension `1350 kg f` . After same time the tension drops to `1000 kg f` and the lift comes to rest at a height of `25 m` above its intial point `(1 kg - f = 9.8 N)` What is the height at which the tension changes ?A. `10.8 m`B. `12.5 m`C. `14.3 m`D. `16 m` |
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Answer» Correct Answer - C Acceleration `a_(1) = (1350 xx 9.8 - 1200 xx 9.8)/(1200)` `= 1.225 m//s^(2)` Retardation, `a_(2) = (1200g - 1000g)/(1200)` `= 1.63 m//s^(2)` `h_(1) + h_(2) = 25` …(i) `nu = sqrt(2 a_(1) h_(1))` or `sqrt(2 a_(2) h_(2))` or `2 a_(1) h_(1) = 2 a_(2) h_(2)` `:. (h_(1))/ ( h_(2)) = (a_(2))/(a_(1))` ...(ii) `= (1.63)/(1.225) = 1.33` Solving these equations,we get `h_(1) = 14.3 m` |
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