A light string passes over a frictionless pulley. To one of its ends a

1.	A light string passes over a frictionless pulley. To one of its ends a mass of 6 kg is attachedTo the other end a mass of 10 kg is attached. The tension is the thread is:(A) 24.5 N(C) 79 N(B) 2.45 N(D) 73.5 N
Answer» Let m₁ = 6kg and m₂ = 10kg 10 kg mass is heavier than 6 kg mass . So, 6 kg moves upward and 10 kg moves downward. Let acceleration generated due to motion of bodies is a Now, apply Newton's 2nd law, For 1st body , T - m₁g = m₁a ----(1) For 2nd body,m₂g - T = m₂a -----(2) Solving both equations we get , T = 2m₁m₂g/(m₁ + m₂) Now, put the values of m₁, m₂ and ge.g., T = 2 × 6 × 10 × 9.8/(6 + 10) T = 12 × 98/16 T = 294/4 N = 73.5 N Hence, tension in string = 73.5 N option (d) is correct

A light string passes over a frictionless pulley. To one of its ends a mass of 6 kg is attachedTo the other end a mass of 10 kg is attached. The tension is the thread is:(A) 24.5 N(C) 79 N(B) 2.45 N(D) 73.5 N

Answer»

Let m₁ = 6kg and m₂ = 10kg 10 kg mass is heavier than 6 kg mass . So, 6 kg moves upward and 10 kg moves downward. Let acceleration generated due to motion of bodies is a

Now, apply Newton's 2nd law, For 1st body , T - m₁g = m₁a ----(1)

For 2nd body,m₂g - T = m₂a -----(2)

Solving both equations we get , T = 2m₁m₂g/(m₁ + m₂)

Now, put the values of m₁, m₂ and ge.g., T = 2 × 6 × 10 × 9.8/(6 + 10) T = 12 × 98/16 T = 294/4 N = 73.5 N

Hence, tension in string = 73.5 N

option (d) is correct

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A light string passes over a frictionless pulley. To one of its ends a mass of 6 kg is attachedTo the other end a mass of 10 kg is attached. The tension is the thread is:(A) 24.5 N(C) 79 N(B) 2.45 N(D) 73.5 N

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