A line is perpendicular to the line `2x-3y+5=0` and passes through the points `(15, beta)` and (7, 17)` then value of `beta` will be equal to (A) `35/3` (B) `-35/3` (C) `5` (D) `-5`A. `(35)/(3)`B. `-5`C. `-(35)/(3)`D. `5`

A line is perpendicular to the line `2x-3y+5=0` and passes through the

1.	A line is perpendicular to the line `2x-3y+5=0` and passes through the points `(15, beta)` and (7, 17)` then value of `beta` will be equal to (A) `35/3` (B) `-35/3` (C) `5` (D) `-5`A. `(35)/(3)`B. `-5`C. `-(35)/(3)`D. `5`
Answer» Slope of the line `2x-3y+17=0` is `(2)/(3)=m_(1)`, (let) and the slope of line joining the points `(7,17)` and `(15,beta)` is `(beta-17)/(15-7)=(beta-17)/(8)=m_(2)`(let) According to the question, `m_(1)m_(2)=-1` `implies(2)/(3)xx(beta-17)/(8)=-1impliesbeta-17=-12impliesbeta=5`.

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