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The equation of the line which bisects the obtuse angle between the line `x-2y+4=0` and `4x-3y+2=0` is |
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Answer» Given equations of lines are `x-2y+4=0` and `4x-3y+2=0` Here, `a_(1)a_(2)+b_(1)b_(2)=1(4)+(-2)(-3)=10 gt 0` For obtuse angle bisector, we take negative sign. `:. (x-2y+4)/(sqrt(5))=(4x-3y+2)/(5)` `impliessqrt(5)(x-2y+4)=-(4x-3y+2)` `implies(4+sqrt(5))x-(2sqrt(5)+3)y+(4sqrt(5)+2)=0` |
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