1.

The equation of the line which bisects the obtuse angle between the line `x-2y+4=0` and `4x-3y+2=0` is

Answer» Given equations of lines are
`x-2y+4=0` and `4x-3y+2=0`
Here, `a_(1)a_(2)+b_(1)b_(2)=1(4)+(-2)(-3)=10 gt 0`
For obtuse angle bisector, we take negative sign.
`:. (x-2y+4)/(sqrt(5))=(4x-3y+2)/(5)`
`impliessqrt(5)(x-2y+4)=-(4x-3y+2)`
`implies(4+sqrt(5))x-(2sqrt(5)+3)y+(4sqrt(5)+2)=0`


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