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A line passes through the point (2, 2) and is perpendicular to the line 3x + y = 3. Its y-intercepts is A. \(\frac{1}{3}\) B. \(\frac{2}{3}\) C. 1 D. \(\frac{4}{3}\) |
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Answer» The equation of the line perpendicular to 3x + y = 3 is given below: x – 3y + λ = 0 This line passes through (2, 2). 2 – 6 + λ = 0 ⇒ λ = 4 So, the equation of the line will be x – 3y + 4 = 0 ⇒ y = 13x + 43 Hence, the y-intercept is \(\frac{4}{3}\). |
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