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Find the y-intercept of the line whose slope is 4 and which has x-intercept 5. |
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Answer» Given, slope = 4, x-intercept = 5 Since the x-intercept of the line is 5, it passes through (5, 0). Equation of the line in slope point form is y – y = m(x – x ) Equation of the required line is y – 0 = 4(x – 5) y = 4x – 20 4x – y = 20 4x/20 - y/20 = 1 x/5 + y/(-20) = 1 This equation is of the form x/a + y/b = 1 where x-intercept = b, y-intercept = -20 |
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