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Find the value of k for which the points P(k, -1), Q(2,1) and R(4,5) are collinear. |
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Answer» Given, points P(k, – 1), Q (2, 1) and R(4, 5) are collinear. ∴ Slope of PQ = Slope of QR . ∴ \(\frac {1-(-1)}{2-k} = \frac {5-1}{4-2}\) ∴ \(\frac {2}{2-k} = \frac {4}{2}\) ∴ 4 = 4 (2 – k) ∴ 1 = 2 – k ∴ k = 2 – 1 = 1 |
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