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A liquid Flows through a pipe 2.0 mm radius and 20 cm length under a pressure `10^(3)" dyne "cm^(-2)`. Determine the rate of flow and the speed of the liquid coming out of the tube. The coefficient of viscosity of the liquid is 1.25 centipoise. |
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Answer» Here, `r = 2.0 mm = 0.2 cm , l=20 cm , p=10^(3)" dyne "cm^(-2) , eta = 1.25 " centipoise "= 0.0125" poise"` Rate of flow of liquid through the tube is `V= (pi p r^(4))/(8 eta l) = ((3.142)xx10^(3)xx (0.2)^(4))/(8 xx 0.0125 xx 20) = 2.51 cm^(3) s^(-1)` Speed of liquid, `upsilon = V/(pi r^(2)) = (2.51)/(3.142 xx (0.2)^(2))= 20 cm s^(-1)`. |
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