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A liquid of density `rho` and surface tension S rises to a height h in a capillary tube of diameter D. what is the weight of the liquid in the capillary tube? Angle of contact is `0^(@)`. |
Answer» Weight of liquid in the capillary tube is `W=mg = pi r^(2)h rho g` We know that, `h=(2 S cos theta)/(r rho g) = (2S)/(r rho g)` `:. W = pi r^(2) rho g xx (2S)/(r rho g) = pi xx 2r xx S` `= pi D S`. |
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