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InterviewSolution
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A locomotive of mass m starts moving sothat its velocity varies according to the lawv = k-/s, where k is constant and s is thedistance covered. Find the total workperformed by all the forces which are actingon the locomotive during the first t secondsafter the beginning of motion..91 4.41 4.4 |
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Answer» Ds/dt = ksqrt(s) s^(-1/2) ds = k dt s^(1/2) / (1/2) = kt 2sqrt(s) = kt s = k^2 t^2 / 4 a = d2s / dt2 = k^2 / 2 dW = F dS = ma dS Since the force is constant, W = ma integral(dS) = ma S = (mk^2 / 2) x (k^2 t^2 / 4)= 1/8*mk^4t^2 option - A |
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