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A loop and a disc have same mass and roll without slipping with the same linear velocity `v`. If the total kinetic energy of the loop is `8 J`, the kinetic energy of the disc must be.A. `8J`B. `6J`C. `16J`D. `4J` |
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Answer» Correct Answer - B Total kinetic energy of loop `=1/2mv^(2)+1/2lomega^(2)` `=1/2mv^(2)+1/2(mr^(2))(v^(2))/(r^(2))=mv^(2)=8` Again total kinetic energy of disc `=1/2mv^(2)+1/2lomega^(2)=1/2mv^(2)+1/2xx1/2mr^(2)xx(v^(2))/(r^(2))` `=1/2mv^(2)+1/4mv^(2)=3/4mv^(2)=3/4xx8J=6J` |
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