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A loop and a disc have same mass and roll without slipping with the same linear velocity `v`. If the total kinetic energy of the loop is `8 J`, the kinetic energy of the disc must be. |
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Answer» Correct Answer - 6 Total kinetic energy of loop `=1/2Iomega+1/2Mv^(2)` `=1/2(MR^(2)omega^(2))+1/2Mv^(2)=Mv^(2)=8j(given)` Total kinetic energy of disc `=1/2Iomega^(2)+1/2Mv^(2)` `-=1/2(1/2MR^(2))((v^(2))/(R^(2)))+1/2Mv^(2)=3/4Mv^(2)=3/4(8)=6J` |
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