A magnet is cut in three equal parts by cutting it perpendicular to its length. The time period of original magnet is `T_0` in a uniform magnetic field B. Then, the time period of each part in the same magnetic field isA. `(T_(0))/(2)`B. `(T_(0))/(3)`C. `(T_(0))/(4)`D. None of these

A magnet is cut in three equal parts by cutting it perpendicular to it

1.	A magnet is cut in three equal parts by cutting it perpendicular to its length. The time period of original magnet is `T_0` in a uniform magnetic field B. Then, the time period of each part in the same magnetic field isA. `(T_(0))/(2)`B. `(T_(0))/(3)`C. `(T_(0))/(4)`D. None of these
Answer» Correct Answer - B In the case of vertical cutting, `T_(1)=("Original time period")/(n)` `T_(1)=(T_(0))/(3)` (Here, n = number of equal parts)

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A magnet is cut in three equal parts by cutting it perpendicular to its length. The time period of original magnet is `T_0` in a uniform magnetic field B. Then, the time period of each part in the same magnetic field isA. `(T_(0))/(2)`B. `(T_(0))/(3)`C. `(T_(0))/(4)`D. None of these

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