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A Man Covers A Distance Of 1200 Km In 70 Days Resting 9 Hours A Day, If He Rests 10 Hours A Day And Walks With Speed 1½ Times Of The Previous In How Many Days Will He Cover 840 Km ? |
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Answer» Distance d = 1200km LET S be the speed he walks 15 hours a day(i.e 24 - 9) so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speed so 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs => 490/14 = 35 days So he will TAKE 35 days to cover 840 km. Distance d = 1200km let S be the speed he walks 15 hours a day(i.e 24 - 9) so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speed so 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs => 490/14 = 35 days So he will take 35 days to cover 840 km. |
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