1.

A Man Covers A Distance On Scooter .had He Moved 3 Kmph Faster He Would Have Taken 40 Min Less. If He Had Moved 2kmph Slower He Would Have Taken 40 Min More. The Distance Is?

Answer»

LET distance = x m

Usual rate = y kmph

x/y – x/y+3 = 40/60 hr

2y(y+3) = 9x ————–1

x/y-2 – x/y = 40/60 hr y(y-2) = 3x —————–2

divide 1 & 2 EQUATIONS

by SOLVING we get x = 40.

Let distance = x m

Usual rate = y kmph

x/y – x/y+3 = 40/60 hr

2y(y+3) = 9x ————–1

x/y-2 – x/y = 40/60 hr y(y-2) = 3x —————–2

divide 1 & 2 equations

by solving we get x = 40.



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