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A man is 25m behind a bus, when bus startsacceleration at 2m/s and man starts moving withconstant velocity of 10 m/s. Tine taken by him toboard the bus is(a) 2 s(c) 46o(d) 5 s v |
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Answer» Let time taken by man = time taken by bus =xfor bus:u=0a=2m/s²t=xS=ut+1/2at² =o×x +1/2×2×x² =x²for man :v=10m/st=xS=v×t = 10xdistance travelled by man - distance travelled by bus =25so, 10x-x² =25x²-10x+25=0(x-5)(x-5)=0x=5minimum time = 5sec hit like if you find it useful |
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