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A man of mass 50kg is walking from East to West direction on a leveled road. acceleration due to gravity g=10m per second sq. What is the frictional force acting when the man is standing on the road? |
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Answer» Answer:• Mass=50kg• Acceleration due to gravity=10m/s^2According to NEWTONS SECOND lawForceMass x Acceleration4G all 67Force = 50 x 10Force50kgm/s²Force = 50NHence forthFrictional force acting on the MAN while standing on the road is 50N. |
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