A man standing on the edge of a cliff throws a ball straight up with a

1.	A man standing on the edge of a cliff throws a ball straight up with a speed of 8 Km/h and then throws a ball down with a speed of 8 Km/h from the same position. What is the ratio of speeds with which the ball hit the ground.
Answer» Explanation: Speed of a particle (magnitude of velocity) is the same at same height. So, when the man throws the BALL with speed u, it will return to him with the same speed u. So when man throws the stone UPWARD with speed u and DOWNWARD with speed u, the initial velocity (from the CLIFF) will be the same.

A man standing on the edge of a cliff throws a ball straight up with a speed of 8 Km/h and then throws a ball down with a speed of 8 Km/h from the same position. What is the ratio of speeds with which the ball hit the ground.

Answer»

Explanation:

Speed of a particle (magnitude of velocity) is the same at same height. So, when the man throws the BALL with speed u, it will return to him with the same speed u. So when man throws the stone UPWARD with speed u and DOWNWARD with speed u, the initial velocity (from the CLIFF) will be the same.

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A man standing on the edge of a cliff throws a ball straight up with a speed of 8 Km/h and then throws a ball down with a speed of 8 Km/h from the same position. What is the ratio of speeds with which the ball hit the ground.​

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A man standing on the edge of a cliff throws a ball straight up with a speed of 8 Km/h and then throws a ball down with a speed of 8 Km/h from the same position. What is the ratio of speeds with which the ball hit the ground.