InterviewSolution
Saved Bookmarks
| 1. |
A man stands before a large wall at a distance of 50.0 m and claps his hands at regular intervals. Initially, the interval is large. He gradually reduces the interval and fixes it at a value when the echo of a clap merges with the next clap. If he has to clap 10 times during every 3 seconds, find the velocity of sound in air. |
|
Answer» Correct Answer - A::C He has to clap 10 times in 3 seconds. so, time interval between two clap `=(3/(10 second))` so, the time taken to go the wall `=(v=(3/(20second))` We know `s=vt` `rarrV=s/t=50/(3/20)=333m/s` |
|