A man starts repaying a loan as the first instalment of 10000. If he i

1.	A man starts repaying a loan as the first instalment of 10000. If he increases the instalment by 500 every month, what amount will he pay in 30th instalment?
Answer» To Find: what amount will he pay in the 30^th instalment. Given: first instalment = 10000 and it increases the instalment by 500 every month. ∴ So it form an AP with first term is 10000, common difference 500 and number of instalment is 30 Formula Used: T_n= a + (n - 1)d (Where a is first term, T_n is n^th term and d is common difference of given AP) ∴ T_n = a + (n - 1)d ⇒ T_n = 10000 + (30 - 1)500 ⇒ T_n = 10000 + 29 × 500 ∴ T_n = 10000 + 14500 ⇒ T_n = 24,500 So, he will pay 24,500 in the 30^th instalment.

A man starts repaying a loan as the first instalment of 10000. If he increases the instalment by 500 every month, what amount will he pay in 30th instalment?

Answer»

To Find: what amount will he pay in the 30^th instalment.

Given: first instalment = 10000 and it increases the instalment by 500 every month.

∴ So it form an AP with first term is 10000, common difference 500 and number of instalment is 30

Formula Used: T_n= a + (n - 1)d

(Where a is first term, T_n is n^th term and d is common difference of given AP)

∴ T_n = a + (n - 1)d

⇒ T_n = 10000 + (30 - 1)500

⇒ T_n = 10000 + 29 × 500

∴ T_n = 10000 + 14500

⇒ T_n = 24,500

So, he will pay 24,500 in the 30^th instalment.