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A Man Walks At A Speed Of 2 Km/hr And Runs At A Speed Of 6 Km/hr. How Much Time Will The Man Require To Cover A Distance Of 20 1/2 Km, If He Completes Half Of The Distance, I.e., (10 1/4) Km On Foot And The Other Half By Running ? |
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Answer» We KNOW that Time = Distance/speed REQUIRED time = (10 1/4)/2 + (10 1/4)/6 = 41/8 + 41/6 = 287/24 = 11.9 HOURS. We know that Time = Distance/speed Required time = (10 1/4)/2 + (10 1/4)/6 = 41/8 + 41/6 = 287/24 = 11.9 hours. |
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