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A man weighing 60kg runs along the rails with a velocity of 18kmph and jumps into a car ofmass 1 quintal standing on the rails. Calculate the velocity with which the car will starttravelling along the rails. |
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Answer» Mass of man(m1) = 60kg Initial velocity of man (u1)= 18 km/h=18x5/18=5m/sFinal velocity of man (v1)= (v2) = vMass of car (m2)= 100kgInitial velocity of car (u2) = 0 (as it is in rest)Final velocity of car (v2) = vAccording to law of conservation of momentum,m1u1 +m2u2 = m1v1 + m2v260x5 + 100x0 = 60xv + 100xv300+0 = 160vv = 300/160v = 1.875 m/s |
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