1.

A man weighs 600 N at earth's surface at what height above the surface of Earth will he weigh 300 Newton take radius of the earth to be 6400 km .please answer this question step by step.(Answer is 1600 km)

Answer»

Explanation:

First of all on Earth's surface g is 10m/s2

so the mass of the man is : 600/10 kg

= 60 kg .

so when it's taken to a height x above the Earth's surface its weight is 300 N.

then g there will be : (300/60)m/s2

= 5 m/s2

Now we know on GOING away from the Earth's surface the acceleration due to gravity decreases eventually .

it can be expressed by the formula

g' = g/(1+h/R)^2

here,

g' = g/2

R = 6400km

so putting the values

g/2 = g/(1+h/6400)^2

or , 1/2 = (1+h/6400)^-2

or , 1/2 = (1-2h/6400) [ applying the LAW of binomial THEOREM ]

or, h = 1600 KM.



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