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A mass 2 kg is placed on a smooth horizontal table and connected by a light inextensible string passing over a small smooth pulley at the edge of the table to a mass of 1 kg hanging freely. The acceleration of system and the tension in the string |
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Answer» gm2 = 1kgT is the tension in the string.Net FORCE on m1 = F1F1 = weight of m1 - normal force on m1 + TSince normal force on m1 is equal toweight of m1 they get cancelled.F1 = T T = m1 a T = 2aNet force on m2 = F2F2 = m2 g - TNow F2 = m2 a So m2 a = m2 g - T 1 × a = 1 × 9.8 - 2a a = 9.8 / 3 a = 3.3 m/s 2T = 2AT = 2× 3.3T = 6.6 N |
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