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A mast stands bot een wo cliffs and fires a gun. He hearssee. The distance between the two cliffs is (speed of sound 340 ms)two successive echoe4) 1340 m12) 1330 m(3) 1360 m(4) 1310 |
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Answer» Distance of the person from the nearer cliff, d1= Vxt/2 = 330 x 3/2 = 495 m Distance of the person from the farther cliff, d2= V x t/2 = 330 x 5/2 = 825m Total distance between two cliffs = d1+ d2= 495 + 825 =1320m |
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