1.

A mast stands bot een wo cliffs and fires a gun. He hearssee. The distance between the two cliffs is (speed of sound 340 ms)two successive echoe4) 1340 m12) 1330 m(3) 1360 m(4) 1310

Answer»

Distance of the person from the nearer cliff, d1= Vxt/2

= 330 x 3/2

= 495 m

Distance of the person from the farther cliff, d2= V x t/2

= 330 x 5/2

= 825m

Total distance between two cliffs = d1+ d2= 495 + 825

=1320m



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