1.

A message signal of frequency 10 kHz and peak voltage 10 V is used tomodulate a carrier of frequency 1 MHz and peak voltage 20 V. Determine(i) the modulation index,(ii) the side bands produced.

Answer»

1) Given that Am = 10v and Ac = 20v Where Am = Amplitude of modulated wave Ac = Amplitude of Carrier wave

Modulation index is given by µ = Am/Ac we get, µ = 10/20 = 0.5

2) Side bands The side bands are, (ωᴄ - ωm) and (ωc+ωm) or we can write (fc - fm) and (fc + fm)

Where (ωᴄ - ωm) is the frequency of lower side band,(ωc+ωm) is the frequency of upper side band .

also ωᴄ = carrier wave frequency ωm = modulated wave frequency

∴ Frequency of lower side band = (ωᴄ - ωm) = (1000-10)= 990 KHz

Frequency of upper side band = (ωᴄ + ωm)= (1000+10)= 1010KHz



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