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A message signal of frequency 10 kHz and peak voltage 10 V is used tomodulate a carrier of frequency 1 MHz and peak voltage 20 V. Determine(i) the modulation index,(ii) the side bands produced. |
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Answer» 1) Given that Am = 10v and Ac = 20v Where Am = Amplitude of modulated wave Ac = Amplitude of Carrier wave Modulation index is given by µ = Am/Ac we get, µ = 10/20 = 0.5 2) Side bands The side bands are, (ωᴄ - ωm) and (ωc+ωm) or we can write (fc - fm) and (fc + fm) Where (ωᴄ - ωm) is the frequency of lower side band,(ωc+ωm) is the frequency of upper side band . also ωᴄ = carrier wave frequency ωm = modulated wave frequency ∴ Frequency of lower side band = (ωᴄ - ωm) = (1000-10)= 990 KHz Frequency of upper side band = (ωᴄ + ωm)= (1000+10)= 1010KHz |
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