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A metal cube of mass 460g and density 2.7g/cm cube is suspended half immersed in a liquid og density 0.8g/cm cube using a thread. Find the tension in the thread. |
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Answer» Tension = 3.84N Explanation:since ' a ' = 0=> F net external = 0=> weight of cube = tension + UPTHRUST weight = mg 460g = 46/100 KG => weight = 46g/100 N VOLUME = mass / density density = 2.7 G/cm^3 = 2700 kg/m^3=> volume of cube = 46/270000 m^3ATQ; volume of SOLID submerged = 1/2 x 46/270000 m^3Upthrust = volume of solid submerged x density of liquid x g => U = 1/2 x 46/270000 x 800 x g=> U = 184g/2700 N Tension = 46g/100 - 184g/2700= 1058g/2700Taking g as 9.8 m/s^2Tension = 1058*9.8/2700= 3.84 newtons ( approx.) |
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