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A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4 cm. Find its(i) inner curved surface area,(ii) outer curved surface area,(iii) total surface area |
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Answer» 1) Inner surface area=`2pirh` `=2*22/7*77*2` =968`cm^2` 2) Outer surfacce area=`2pirh` `=2*22/7*2.2*77` =10647.8`cm^2` 3) Total surface area=outer surface area+inner surface area+ring. =968+1064.8+`pi(R^2+r^2)` =2032.8+22/7(4.4^2-4^2) =2034.36`cm^2` |
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