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A metal sphere A of radius a is charged to potential V. What will be its potential if it is enclosed ny a spherical conducting shell B of radius b and the two are connected by a wire ? |
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Answer» If the charge on the sphere of radius a is q, then `V = (1)/(4 pi epsilon _0) q/a` `i.e, q = (4 pi epsilon_0 a) V` Now, when sphere A is enclosed by spherical conductor B and the two are connected by a wire, charge will reside on the outer surface of B and so the potential of B will be `V_B= (1)/(4 pi epsilon _0) q/b = (1)/(4 pi epsilon_0)(4pi epsilon_(0)a)/(b)V = a/b V` Now as sphere A is inside B, so its potential is `V_A = V_B = a/b (V)" " [ V "as a" lt b]`. (##BMS_V03_C03_S01_031_S01##). |
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