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A metal wire of linear mass density of `9.8g//m` is stretched with a tension of `10 kg-wt` between two rigid support `1meter` apart. The wire passes at its middle point between the poles of a permanent magnet, and it vibrates in resonance when carrying an alternating current of frequency `n`. the frequency `n` of the alternating source isA. 50 HzB. 100 HzC. 200 HzD. 25 Hz |
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Answer» Correct Answer - a The wire will vibrate with the same frequency as that of source. This can be considered as an example of forced vibration. `T=10xx9.8 N=98 ` n and `m=9.8 xx 10^(-3)`kg `m^(-1)` Frequency of wire `f=1/(2L) sqrt((T/m))=1/(2xx1) sqrt((98)/(9.8xx10^(-3)))` = 50 Hz |
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