A metalic masss of 1 kg has moment of inertia 1 kg n^2 when rotating about one of its diameters. it is molten and remoulded into a thin uniform disc of the same radius . how much will its moment of inertia be, when roatated about its own axis. please help me by solving on page

A metalic masss of 1 kg has moment of inertia 1 kg n^2 when rotating a

1.	A metalic masss of 1 kg has moment of inertia 1 kg n^2 when rotating about one of its diameters. it is molten and remoulded into a thin uniform disc of the same radius . how much will its moment of inertia be, when roatated about its own axis. please help me by solving on page
Answer» tion:Mass of RING and disc is M=1mkg Moment of INERTIA of ring at diameter (Ir)d=1kgm 2 Rr=RD What we have to find out:-Moment of inertia of disc about own axis =ID= ?Using theorem of perpendicular axes, for a ring M.I about its any diameter, which is given by,(Ir)c=2(Ir)d =2×1 MRr 2 =2kgm 2 Rr 2 =Rd 2 =2 meter Hence, Moment of inertia of disc about own axis is given by,Id= 21 MRd 2 = 21 ×1×2 Id=1kgm 2Hope its help..

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A metalic masss of 1 kg has moment of inertia 1 kg n^2 when rotating about one of its diameters. it is molten and remoulded into a thin uniform disc of the same radius . how much will its moment of inertia be, when roatated about its own axis. please help me by solving on page

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