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A metallic block weighs `15 N` in air. It weights `12 N` when immersed in water and `13 N` when immersed in another liquid. What is the specific gravity of the liquid? |
Answer» (i) Reletaive density of the block `=("weight of the block in air")/("loss in weight of block when immeresed in water") = (15)/(15-12) = 5` (ii) Relative density of the liquid, ` = ("loss of weight n liquid")/("Loss of weight of water") = (15-13)/(15-12)=2/3` |
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