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InterviewSolution
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A metallic cube of side 8cm is under a tangential force. The top face of the cube is sheared through 0.15 mm with respect to the bottom face. Find (a) shearing stain (b) shearing stress and (c ) shearing force. Given , modulus of rigidity of the metal `=2.08 xx 10^(11) dyn e.//cm^(2)` . |
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Answer» Here, length of each side of cube L `8cm` Lateral displacement , `Delta L = 0.15 mm =0.015cm` (a) shearing strain, `theta = (Delta L)/(L) = (0.015)/(8)` `=0.001875`. (b) Shearing stress = `F/A = G theta` `(2.08 xx 10^(11)) xx 0.001875` `=3.9 xx 10^(8) dyn e//cm^(2)`. (c ) Area of face, `A = 8xx8 cm^(2)` As `F=F/(A theta) ir F=GA theta` `:.` Shearing force, `F=GA theta` `=(2.08 xx 10^(11)) xx (8 xx 8 ) xx 0.001875` `=0.25 xx 10^(11) dyn e = 2.5 xx 10^(10) dyn e`. |
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