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A metallic sphere of radius 2 cm is melted to recast into the shape of a cylinder of radius 4 cm. Then the height of the cylinder isA) 1/3 cmB) 4/3 cmC) 2/3 cmD) 1 cm |
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Answer» Correct option is: C) \(\frac{2}{3}\) cm Volume of cylinder = volume of the sphere. = \(\pi r^2h = \frac 43 \pi r^3\) = \(4 \times 4 \times h = \frac 43 \times 2 \times 2 \times 2\). = h = \(\frac {16}3 \times \frac2{16} = \frac 23\) Hence, the height of the cylinder is \(\frac 23\)cm Correct option is: C) \(\frac{2}{3}\) cm |
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