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a meter gauge railway track is to be banked at a circular curve of radius 450m. what should be the elevation of the outer rail above the inner rail for an optimum speed of 54km/hr so that there is no side thrust on the outer rail. |
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Answer» , meter gauge railway track is something like that in the attachment. Now acc. to ques. we need to find the distance/height between OUTER rail above the inner rail.So, from question, we have;Velocity of train = 54 km/H = 15 m/s RADIUS = 450 mlength = 1mNow, we know that, in the case of a banked railway track;Tanθ = v²/rg ( where g is the acceleration DUE to GRAVITY. )= Tanθ = v²/rg= Tanθ = 15²/450 × 9.8= Tanθ = 225 / 4410= Tanθ = 0.0510204= θ = tan⁻¹( 0.0510204 )= θ = 2.9°Now, finally the elevation of outer rail above inner rail;h = l × sinθh = 1 × sin(2.9°)h = 0.05059 mThus, the height of outer rail from inner will be 0.0506 m.__________________________Thank youu! :)) |
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