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A monkey of 25 kg is holding a vertical rope. The rope does not break if a body of mass 30 kg is suspended with the rope exceeds 30 kg. What will be the maximum acceleration with which the monkey can climb up along the rope ? ( Take ,`=10 ms^(-2)`)A. `2 ms^(-2)`B. `2.5 ms^(-2)`C. `3 ms^(-2)`D. `4 ms^(-2)` |
Answer» Correct Answer - A (a) The maximum weight which can be suspended with the rope without breaking it =30 kg-wt. `=30xx10=300N` `therefore 300N=mg+ma` `implie ma=300- mg` `=300-25xx10=50N` `implies a=(50)/(m)=(50)/(25)=2 ms^(-2)` |
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