InterviewSolution
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InterviewSolution
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A mono-atomic ideal gas of two moles is taken through a cyclic process starting from `A` as shwon in the figure below. The volume ratios are `V_(B)//V_(A) = 2` and `V_(D)//V_(A) = 4`. If the temperature `T_(A)` at `A` is `27^(@)C`. Calculate a. The temperature of gas at `B`. b. Heat absorbed or evolved in each process. c. Total wrok done in cyclic process. |
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Answer» `A rarrB:` (It is isobaric procee) `(V_(A))/(T_(A)) - (V_(B))/(T_(B))` `:. T_(B) = (V_(B))/(V_(A)) xx T_(A) = 2 xx 300 = 600K` `q_(AB) = nC_(P)Delta_(T) = 2xx (5)/(2)R DeltaT` `= 2 xx (5)/(2) xx2xx300 = 3000cal` `B rarrC`: (Isothermal process) `DeltaU = 0` `:. q_(BC) = w = 2.303nRT log_(10) ((V_(C))/(V_(B)))` `= 2.303 xx2xx2xx600 log.(4)/(2)` `C rarrD:` (Isochric process) `q_(CD) = nC_(v) DeltaT = 2xx (3)/(2) xx 2 (-300) =- 1800cal` `D rarA`: (Isochoric procee) `q_(DA) = 2.303 nRT_(A) log_(10). (V_(A))/(V_(D))` `= 2.303 xx 2xx 2xx200 log.(1)/(4)` Total heat change `= 3000 + (1.663 xx 10^(3)) - 1800 - (1.663 xx 10^(3)) = 1200 cal` Work done `=- 1200 cal` |
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