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A monoprotic acid in `0.1 M` solution has `K_(a)=1.0xx10^(-5)`. The degree of dissociation for acid isA. `1.0%`B. `99.9%`C. `0.1%`D. `99%` |
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Answer» Correct Answer - A `K_(a)=c alpha^(2)` or `1.0xx10^(-5)=0.1xxalpha^(2)` `:. alpha=10^(-2)` or `1%` |
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