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A motor of power 0.98 kW drags a mass 100kg through 2m on asurface having coefficient of friction O.3. Time of that mass is1) 0.4 sec2)0.61 sec.2 sec4) 0.2 sec |
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Answer» Power =force * displacement / timegivenP=0.98 kWm=100 kgs=4 mu= 0.3( from s=at sqr)F=mu ma (a = s/t sqr)0.3*100*4/t sqr120/t sqrpower =force * displacement / time0.98 kW = 120/t sqr * 4/t |
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