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A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time. |
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Answer» Answer:Answer U=5m/sv=?a=0.2m/s t=10sec v=u+at v=5+0.2×10 v=7m/s
Now distance TRAVELED, s=? v 2 =u 2 +2as 7 2 =5 2 +2×0.2×s 49=25+0.4s 49−25=0.4s s= 0.4 24
s=60m
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