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a moving particle reduce its velocity from 10 metre per second square to 5 metre per second square in 5 second find acceleration |
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Answer» Answer: hope it helps you Explanation: A = (V - u)/t = (0 - u)/t = -u / (5 s) S = ut + 0.5at² 100 = 5u + (0.5 × [-u / (5 s)] × (5 s)²) 100 = 5u - 2.5u 100 = 2.5u u = 40 m/s If u = 40 m/s then a = -u / (5 s) = -(40 m/s) / (5 s) = -8 m/s² DISPLACEMENT covered in 10 seconds S = ut + 0.5at² = (40 m/s × 10 s) + [0.5 × (-8 m/s² × (10 s)²] = 0 m Particle travelled 100 m in first 5 seconds and in next 5 seconds it travels 100 m back to initial position. Hence we got Displacement after 10 seconds equal to zero. |
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