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A narrow capillary tube when dipped in beaker containing water, the rise is 20 cm . If the area of cross section of the bore is reduced to `(1//4)^(th)` calue , water will rise to a height ofA. 10 cmB. 20 cmC. 40 cmD. 80 cm |
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Answer» Correct Answer - C ` A_(2)= 1/4 A_(1)` `pir_(2)^(2)=1/4pir_(1)^(2)` `r_(2)=1/2r_(1)` `h_(2)=(h_(1)r_(1))/(r_(2)) =(h_(1)r_(1))/(1/2r_(2))=2h_(1)=2xx20` =40 cm |
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