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A negligibly small current is passed through a wire of length 15 m and uniform cross- (2)section 6.0 × 1 07 m, and its resistance is measured to be 5.0 Ω. What is the resistivity ofthe material at the temperature ofthe experiment? |
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Answer» As, R = p L/A and , R = 5 ohm ; L= 15m ; A = 6×10^-7m^2 So, resistivity, p = RA/L = 5×6×10^-7/15 or, resistivity , p = 2×10^-7 Ώm Like my answer if you find it useful! |
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