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A nucles with mass number `220`initilly at rest enits an `a - particle`. If the `Q` value of the reaction is `5.5MeV`, calculate the kinetic energy of the `a - particle`A. `4.4 MeV`B. `5.4 MeV`C. `5.6 MeV`D. `6.5 MeV` |
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Answer» Correct Answer - B By conservation of momentum , `p_(1) = p_(2) ` ` sqrt(2K_(1) m_(1)) = sqrt(2K_(2) m_(2)) ` `rArr sqrt(2K_(1)(216)) = sqrt(2K_(2)(4)) ` rArr K_(2) = 54K_(1) ` …(i) `Also , K_(1) + K_(2) = 5.5 MeV` …(ii) solve equation (i) and (ii) |
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